Question
How to present each page from a pagelist property into a separate screen?
We do have a pagelist property with 10 pages in it(source from a data table). Need to display each page from the list into a separate screen with forward and backward navigation buttons. Can someone suggest with the best approach to achieve this scenario. TIA
Create a new section in the data class (pageList.pxResults() class)
Use repeat grid, enable pagination with size "1" and include the above section
Hope this helps..
After implementing this approach, how can I display the next and previous buttons instead of using the Pagination?
Say I do have a pagelist in work class with definition into data class. as per your suggestion I've created a section in data class, here how can we include work class pagelist property to create a repeating grid?
If the Applies To class of PageList property is Work, then you need to define the section only in work to implement this approach. Once you defined the section in Work, drag a Repeat Grid and Select source as Property and include your PageList Property. Now the columns of your grid will only accept the Page definition class of PageList property. As per your statement, since your PageList property is defined as data class, you can embed the section directly into one of the cell of repeat grid.
Find this word file if any new person needs to copy the data from one pagelist to another pagelist
You can do this by making use of a ScreenFlow with split-forEach. Though this article is old but gives you various options on how it can be done.
https://pdn.pega.com/how-use-split-foreach-shapes-screen-flows