Question 1 Replies 2614 Views × Close popover MD MAZAHARUL HAQUE (MAZAHARULH) CTS CTS NL View Profile Send Message MAZAHARULH Member since 2014 4 posts CTS Posted: April 4, 2017 Last activity: April 4, 2017 Posted: 4 Apr 2017 3:51 EDT Last activity: 4 Apr 2017 13:50 EDT Closed Solved replaceAll function not working Hi, I have a parameter which contains "\". I want to replace with "". I have used replaceAll function like below. Param.Test=@String.replaceAll(Param.Test,"\",""). And its not working. Can you please suggest on this? Thanks, Mazaharul ***Updated by Moderator: Marissa to update categories*** Case Management System Administration User Experience × Close popover Facebook Twitter Linkedin Email Copy Link Copied! Moderation Team has archived post, learn more × Close popover This thread is closed to future replies. Content and links will no longer be updated. If you have the same/similar Question, please write a new Question. Accepted Solution Posted: 4 years ago Posted: 4 Apr 2017 3:53 EDT × Close popover Akshay Kumar Sinha (AkshaySinha) PEGA Senior Technical Solutions Engineer Pegasystems Inc. IN View Profile Send Message AkshaySinha PEGA replied to MAZAHARULH Hello Mazaharul, Can you please look into the below article and try the provided suggestion in the article : https://pdn.pega.com/community/pega-product-support/question/replaceall-not-working-expected Thanks.